Required role: | Consumer |
GET | /share/refer-friend-link | Create a friend referral link | The link contains a JWT token with the identity of the referring user as well as the expiration of the referral. |
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library ConsumerApi;
import 'package:servicestack/servicestack.dart';
class ReferFriendLinkResponse implements IConvertible
{
String? linkWithReferFriendToken;
ReferFriendLinkResponse({this.linkWithReferFriendToken});
ReferFriendLinkResponse.fromJson(Map<String, dynamic> json) { fromMap(json); }
fromMap(Map<String, dynamic> json) {
linkWithReferFriendToken = json['linkWithReferFriendToken'];
return this;
}
Map<String, dynamic> toJson() => {
'linkWithReferFriendToken': linkWithReferFriendToken
};
getTypeName() => "ReferFriendLinkResponse";
TypeContext? context = _ctx;
}
class ReferFriendLinkRequest implements IGet, IConvertible
{
ReferFriendLinkRequest();
ReferFriendLinkRequest.fromJson(Map<String, dynamic> json) : super();
fromMap(Map<String, dynamic> json) {
return this;
}
Map<String, dynamic> toJson() => {};
getTypeName() => "ReferFriendLinkRequest";
TypeContext? context = _ctx;
}
TypeContext _ctx = TypeContext(library: 'ConsumerApi', types: <String, TypeInfo> {
'ReferFriendLinkResponse': TypeInfo(TypeOf.Class, create:() => ReferFriendLinkResponse()),
'ReferFriendLinkRequest': TypeInfo(TypeOf.Class, create:() => ReferFriendLinkRequest()),
});
Dart ReferFriendLinkRequest DTOs
To override the Content-type in your clients, use the HTTP Accept Header, append the .xml suffix or ?format=xml
The following are sample HTTP requests and responses. The placeholders shown need to be replaced with actual values.
GET /share/refer-friend-link HTTP/1.1 Host: unstable-consumer-api.brovs.com Accept: application/xml
HTTP/1.1 200 OK Content-Type: application/xml Content-Length: length <ReferFriendLinkResponse xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://schemas.datacontract.org/2004/07/Api.Dto"> <LinkWithReferFriendToken>String</LinkWithReferFriendToken> </ReferFriendLinkResponse>